Matematika Sekolah Menengah Atas bantuin kk..makasih ​

bantuin kk..makasih ​

Penyelesaian:

a.)√18/√2

=√18/2

=√9

=3

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b.)6/√8

=6/√8×√8/√8

=6√8/8

=¾√8

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c.)√12/4√2

=√12/4√2×4√2/4√2

=4√24/16×2

=4√4×6/32

=8√6/32

=8/32 √6

=¼√6

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d.)

√24/45×√9/2

=√216/90

=√36×6/9×10

=6√6/3√10

=2 √6/10

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e.)√0,000049

=√(4,9×10^-6)

=7×10^-3

=0,007

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f.)√0,00000256

=√(2,56×10^-6)

=1,6×10^-3

=0,0016

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Materi : Bentuk Akar dan Pangkat

Bagian A

√18 ÷ √2 = √(18/2) = √9 = 3

Bagian B

6/√8

= 6(√8)/(√8)²

= 6(√8)/8

= ¾( √8 )

= ¾( 2√2 )

Bagian C

√12/4√2

= 4√2( √12 )/( 4√2 )²

= 4( √24 )/( 16[2] )

= 4( 2√6 )/( 32 )

= 8( √6 )/32

= ¼( √6 )

Bagian D

√24/√45 × √9/√2

= √(24×9)/√(45×2)

= √(4×9×6)/√(9×10)

= ( 2 × 3 )√6/( 3 )√10

= 6√6/3√10

= ( 6/3 )√6/√10

\_______________/

= 2√6( √10 )/( √10 )²

= 2( √60 )/100

= ( 1/50 )√(4×15)

= ( 1/25 )√15

Bagian E

√0,000049

= √( 4,9 × 10-⁶ )

= 0,7 × 10-³

= 0,0007

Bagian F

√0.00000256

= √( 2,56 × 10-⁶ )

= 1,6 × 10-³

= 0,16 × 10-²

= 0,0016

Semoga bisa membantu

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